这个练习让您编写处理数组和结构的函数。下面是程序的框架,请提供其中描述的函数,以完成该程序。 #include <iostream> using namespace std; const int SLEN = 30; struct student {       char fullname[SLEN];       char hobby[SLEN];       int ooplevel; }; // getinfo() has two arguments; a pointer to the first element of // an array of student structures and an int representing the // number of elements of the array. The function solicits and // stores data about students. It terminates input upon filling // the array or upon encountering a blank line for the student // name. The function returns the actual number of array elements // filled. int getinfo (student pa[], int n); // display1() takes a student structure as an argument // and displays its contents void display1 (student st); // display2() takes the address of student structure as an // argument and displays the structure’s contents void display2 (const student * ps); // display3() takes the address of the first element of an array // of student structures and the number of array elements as // arguments and displays the contents of the structures void display3 (const student pa[], int n); int main() {       cout << "Enter class size; ";       int class size;       cin >> class_size;       while (cin.get() != ‘n’)             coutinue;        student * ptr_stu = new student [class_size];        int entered = getinfo(ptr_stu, class_size);        for (int i = 0; i < entered; i++)        {              display1(ptr_stu[i]);              display2(&ptr_stu[i]);         }         display3(ptr_stu, entered);         delete [] ptr_stu;         cout << "Donen";         return 0; }-笔试面试资料

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提供答案分析,通过本文《这个练习让您编写处理数组和结构的函数。下面是程序的框架,请提供其中描述的函数,以完成该程序。 #include <iostream> using namespace std; const int SLEN = 30; struct student {       char fullname[SLEN];       char hobby[SLEN];       int ooplevel; }; // getinfo() has two arguments; a pointer to the first element of // an array of student structures and an int representing the // number of elements of the array. The function solicits and // stores data about students. It terminates input upon filling // the array or upon encountering a blank line for the student // name. The function returns the actual number of array elements // filled. int getinfo (student pa[], int n); // display1() takes a student structure as an argument // and displays its contents void display1 (student st); // display2() takes the address of student structure as an // argument and displays the structure’s contents void display2 (const student * ps); // display3() takes the address of the first element of an array // of student structures and the number of array elements as // arguments and displays the contents of the structures void display3 (const student pa[], int n); int main() {       cout << "Enter class size; ";       int class size;       cin >> class_size;       while (cin.get() != ‘n’)             coutinue;        student * ptr_stu = new student [class_size];        int entered = getinfo(ptr_stu, class_size);        for (int i = 0; i < entered; i++)        {              display1(ptr_stu[i]);              display2(&ptr_stu[i]);         }         display3(ptr_stu, entered);         delete [] ptr_stu;         cout << "Donen";         return 0; }-笔试面试资料》可以理解其中的代码原理,这是一篇很好的求职学习资料
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这个练习让您编写处理数组和结构的函数。下面是程序的框架,请提供其中描述的函数,以完成该程序。
#include <iostream> using namespace std; const int SLEN = 30; struct student {       char fullname[SLEN];       char hobby[SLEN];       int ooplevel; }; // getinfo() has two arguments; a pointer to the first element of // an array of student structures and an int representing the // number of elements of the array. The function solicits and // stores data about students. It terminates input upon filling // the array or upon encountering a blank line for the student // name. The function returns the actual number of array elements // filled. int getinfo (student pa[], int n); // display1() takes a student structure as an argument // and displays its contents void display1 (student st); // display2() takes the address of student structure as an // argument and displays the structure's contents void display2 (const student * ps); // display3() takes the address of the first element of an array // of student structures and the number of array elements as // arguments and displays the contents of the structures void display3 (const student pa[], int n); int main() {       cout << "Enter class size; ";       int class size;       cin >> class_size;       while (cin.get() != 'n')             coutinue;        student * ptr_stu = new student [class_size];        int entered = getinfo(ptr_stu, class_size);        for (int i = 0; i < entered; i++)        {              display1(ptr_stu[i]);              display2(&ptr_stu[i]);         }         display3(ptr_stu, entered);         delete [] ptr_stu;         cout << "Donen";         return 0; } 

这个练习让您编写处理数组和结构的函数。下面是程序的框架,请提供其中描述的函数,以完成该程序。  #include &lt;iostream&gt; using namespace std; const int SLEN = 30; struct student {       char fullname[SLEN];       char hobby[SLEN];       int ooplevel; }; // getinfo() has two arguments; a pointer to the first element of // an array of student structures and an int representing the // number of elements of the array. The function solicits and // stores data about students. It terminates input upon filling // the array or upon encountering a blank line for the student // name. The function returns the actual number of array elements // filled. int getinfo (student pa[], int n); // display1() takes a student structure as an argument // and displays its contents void display1 (student st); // display2() takes the address of student structure as an // argument and displays the structure's contents void display2 (const student * ps); // display3() takes the address of the first element of an array // of student structures and the number of array elements as // arguments and displays the contents of the structures void display3 (const student pa[], int n); int main() {       cout &lt;&lt; &quot;Enter class size; &quot;;       int class size;       cin &gt;&gt; class_size;       while (cin.get() != 'n')             coutinue;        student * ptr_stu = new student [class_size];        int entered = getinfo(ptr_stu, class_size);        for (int i = 0; i &lt; entered; i++)        {              display1(ptr_stu[i]);              display2(&amp;ptr_stu[i]);         }         display3(ptr_stu, entered);         delete [] ptr_stu;         cout &lt;&lt; &quot;Donen&quot;;         return 0; } 区块链毕设学生520230672号
#include <iostream> using namespace std;  const int SLEN=30;  struct student { 	char fullname[SLEN]; 	char hobby[SLEN]; 	int ooplevel; };  int getinfo(student pa[],int n); void display1(student st); void display2(const student*ps); void display3(const student pa[],int n);  int main() { 	cout<<"Enter the calss size:"; 	int class_size; 	cin>>class_size; 	student * ptr_stu = new student [class_size]; 	int entered=getinfo(ptr_stu,class_size); 	for (int i = 0; i < class_size; i++) 	{ 		display1(ptr_stu[i]); 		display2(&ptr_stu[i]); 	} 	display3(ptr_stu,entered); 	delete[] ptr_stu; 	cout<<"Done"<<endl; 	system("pause"); 	return 0; }  int getinfo(student pa[],int n) { 	int i=0; 	for ( i = 0; i < n; i++) 	{ 		if (!cin) 	   { 		cin.clear(); 		while(cin.get()!='n') 			continue; 		cout<<"Bad input"<<endl; 		break; 	   } 		cout<<"Enter the fullname #"<<i+1<<": "; 		cin>>pa[i].fullname; 		cout<<"Enter the hobby #"<<i+1<<":"; 		cin>>pa[i].hobby; 		cout<<"Enter the opplevel #"<<i+1<<":"; 		cin>>pa[i].ooplevel; 		 	} 	return i; }  void display1(student st) { 	cout<<"Student name:"<<st.fullname<<endl; 	cout<<"Student hobby:"<<st.hobby<<endl; 	cout<<"Student level:"<<st.ooplevel<<endl; } void display2(const student*ps) { 	cout<<"Student name:"<<ps->fullname<<endl; 	cout<<"Student hobby:"<<ps->hobby<<endl; 	cout<<"Student level:"<<ps->ooplevel<<endl; } void display3(const student pa[],int n) { 	for (int i = 0; i < n; i++) 	{ 		cout<<"Student name:"<<pa[i].fullname<<endl; 	    cout<<"Student hobby:"<<pa[i].hobby<<endl; 	    cout<<"Student level:"<<pa[i].ooplevel<<endl; 	} }

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qklbishe.com区块链毕设代做网专注|以太坊fabric-计算机|java|毕业设计|代做平台 » 这个练习让您编写处理数组和结构的函数。下面是程序的框架,请提供其中描述的函数,以完成该程序。 #include <iostream> using namespace std; const int SLEN = 30; struct student {       char fullname[SLEN];       char hobby[SLEN];       int ooplevel; }; // getinfo() has two arguments; a pointer to the first element of // an array of student structures and an int representing the // number of elements of the array. The function solicits and // stores data about students. It terminates input upon filling // the array or upon encountering a blank line for the student // name. The function returns the actual number of array elements // filled. int getinfo (student pa[], int n); // display1() takes a student structure as an argument // and displays its contents void display1 (student st); // display2() takes the address of student structure as an // argument and displays the structure’s contents void display2 (const student * ps); // display3() takes the address of the first element of an array // of student structures and the number of array elements as // arguments and displays the contents of the structures void display3 (const student pa[], int n); int main() {       cout << "Enter class size; ";       int class size;       cin >> class_size;       while (cin.get() != ‘n’)             coutinue;        student * ptr_stu = new student [class_size];        int entered = getinfo(ptr_stu, class_size);        for (int i = 0; i < entered; i++)        {              display1(ptr_stu[i]);              display2(&ptr_stu[i]);         }         display3(ptr_stu, entered);         delete [] ptr_stu;         cout << "Donen";         return 0; }-笔试面试资料

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