In following code, expression#1 ( ) let $point get the reference of @ARGV, expression#1 should be: #!/usr/contrib/bin/perl -w expression#1 print "ARGV = ", join(",", expression#2), "n";
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In following code, expression#1 ( ) let $point get the reference of @ARGV, expression#1 should be:
#!/usr/contrib/bin/perl -w
expression#1
print "ARGV = ", join(",", expression#2), "n";
引用就是指针，一个标量类型可以指向标量、数组、hash、子程序。
46:48
以上就是关于问题In following code, expression#1 ( ) let $point get the reference of @ARGV, expression#1 should be:
#!/usr/contrib/bin/perl -w
expression#1
print "ARGV = ", join(",", expression#2), "n";的答案
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