阅读以下代码片段: String Scanme = "abcdefghijkl"; String Delim = "[aeoiu]"; Scanner Scanner = New Scanner(scanme); Scanner.usedelimiter(delim); While (scanner.hasnext()) System.out.print(scanner.next()); 输出结果是:( )
区块链毕设网qklbishe.com为您提供问题的解答
阅读以下代码片段:
String Scanme = "abcdefghijkl";
String Delim = "[aeoiu]";
Scanner Scanner = New Scanner(scanme);
Scanner.usedelimiter(delim);
While (scanner.hasnext())
System.out.print(scanner.next());
输出结果是:( )
为什么呢
39:49
以上就是关于问题阅读以下代码片段: String Scanme = "abcdefghijkl"; String Delim = "[aeoiu]"; Scanner Scanner = New Scanner(scanme); Scanner.usedelimiter(delim); While (scanner.hasnext()) System.out.print(scanner.next()); 输出结果是:( )的答案
欢迎关注区块链毕设网-
专业区块链毕业设计成品源码,定制。
区块链NFT链游项目方科学家脚本开发培训